获取浏览器上的querystring

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const getQuery = key =>
location.search.substr(1).split('&')
.map(x => x.split('='))
.filter( ([k]) => Array.isArray(key) ? key.includes(k):k=== key)
.reduce((r, [k,v]) => Array.isArray(key) ? Object.assign(r || {},{[k]:v}): v, null)

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